【练习题】数组全排列

一、调库函数

next_permutation

这里写图片描述

class Solution {
public:
    vector<vector<int> > permute(vector<int>& num) 
    {
        vector<vector<int>> res;
        sort(num.begin(),num.end());
        do  
        { 
           res.push_back(nums);
        }while(next_permutation(num.begin(),num.end())); 
        return res; 
    }
};

二、自己实现

class Solution {
public:
    void DFS(vector<int> &num, vector<int> &visited, vector<vector<int>> &res){
        //够一组数据
        if (num.size() == visited.size()){
            res.push_back(visited);
            return;
        }
        vector<int>::iterator it;
        for (int i = 0; i < num.size(); i++)
        {
            // 判断num[i]是否已经访问过
            it= find(visited.begin(), visited.end(), num[i]);
            // 如果没有访问过
            if (it== visited.end())
            {
                visited.push_back(num[i]);
                DFS(num, visited, result);
                visited.pop_back();
            }
        }
        return;
    }
    vector<vector<int> > permute(vector<int> &num) 
    {
        vector<vector<int> > result;
        if (num.empty()){
            return res;
        }
        vector<int> visited;
        DFS(num, visited, res);
        return res;
    }
};

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转载自blog.csdn.net/lindaxym/article/details/80969225
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