mysql:
根节点到子孙节点:(参考:https://www.2cto.com/database/201403/283731.html)
drop FUNCTION if EXISTS getChildList;
CREATE FUNCTION `getChildList`(rootId INT)
RETURNS varchar(1000)
BEGIN
DECLARE sChildList VARCHAR(1000);
DECLARE sChildTemp VARCHAR(1000);
SET sChildTemp =cast(rootId as CHAR);
WHILE sChildTemp is not null DO
IF (sChildList is not null) THEN
SET sChildList = concat(sChildList,',',sChildTemp);
ELSE
SET sChildList = concat(sChildTemp);
END IF;
SELECT group_concat(id) INTO sChildTemp FROM user_role where FIND_IN_SET(parentid,sChildTemp)>0;
END WHILE;
RETURN sChildList;
END;
/*获取子节点*/
/*调用: 1、select getChildList(0) id; 2、select * 5From user_role where FIND_IN_SET(id, getChildList(2));*/
子节点到根节点
drop FUNCTION if EXISTS getParentList;
CREATE FUNCTION `getParentList`(rootId INT)
RETURNS varchar(1000)
BEGIN
DECLARE sParentList varchar(1000);
DECLARE sParentTemp varchar(1000);
SET sParentTemp =cast(rootId as CHAR);
WHILE sParentTemp is not null DO
IF (sParentList is not null) THEN
SET sParentList = concat(sParentTemp,',',sParentList);
ELSE
SET sParentList = concat(sParentTemp);
END IF;
SELECT group_concat(parentid) INTO sParentTemp FROM user_role where FIND_IN_SET(id,sParentTemp)>0;
END WHILE;
RETURN sParentList;
END;
/*获取父节点*/
/*调用: 1、select getParentList(6) id; 2、select * From user_role where FIND_IN_SET(id, getParentList(2));*/
oracle:
子节点向根节 level 关键字指所在层次
select level,a.* from TF_REGION a start with REGION_CODE =130000 connect by prior PARENT_CODE =REGION_CODE
START WITH...CONNECT BY PRIOR子句实现递归查询
--根据regioncode 获取国家code (获取最高级)
select distinct(REGION_CODE) from (
SELECT * FROM TF_REGION g START WITH g.REGION_CODE =5002
CONNECT BY PRIOR
g.PARENT_CODE = g.REGION_CODE
) t where nvl(t.DEL_FLAG,0)=0 and t.region_level=1 ;
根节点遍历子节点
select level,a.* from TF_REGION a start with PARENT_CODE=1 connect by prior REGION_CODE=PARENT_CODE
注意:最后的REGION_CODE=PARENT_CODE 是包括子孙节点,PARENT_CODE=REGION_CODE是只有子节点
start with 后面所跟的就是就是递归的种子,也就是递归开始的地方;
connect by prior后面的字段顺序是有讲究的;