from random import *
def sam():
brithday = []
res = []
for i in range(1000):
n = randint(1,365)
brithday.append(n)
for j in range(23):
k = brithday[randint(0,999)]
res.append(k)
for i in range(1,23):
for j in range(i):
if res[i] == res[j]:
return True
return False
counts = 0
for i in range(100):
if sam():
counts +=1
else:
continue
print("至少两人相同的概率是{}%".format(counts))
python 学习 生日悖论分析 DAY20
猜你喜欢
转载自blog.csdn.net/u011451186/article/details/81116329
今日推荐
周排行