程序员的action

spring2.08 webwork2.24
注入Action中的service出现问题，注入的service，和引用的service不是同一个对象。
无论是不是singleton都出现execute方法里面引用的service为null，声明为singleton="true"时初始化时setter方法里的service有效。
或者把service声明为static的也没问题。

Action

Java代码收藏代码
public class SystemAction extends ActionSupport implements ModelDriven{
    SystemModel sm = new SystemModel();
    private SystemService systemService;

    public String execute() throws Exception {
        System.out.println("in execute systemservice is "+systemService);
        systemService.TestSystemDAO();
        return SUCCESS;
    }

..setter..省略

Action的注入
Java代码收藏代码
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">
<beans>
        <bean id="systemAction" class="net.xx.control.action.SystemAction" singleton="false">
        <property name="systemService">
            <ref bean="userService"/>
        </property>
        </bean>
</beans>

xwork.xml

Java代码收藏代码
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN" "http://www.opensymphony.com/xwork/xwork-1.0.dtd">
<xwork>
    <include file="webwork-default.xml" />
    <package name="default" extends="webwork-default">
        <interceptors>
            <interceptor-stack name="modelParamsStack">
                <interceptor-ref name="params" />
                <interceptor-ref name="model-driven"/>
            </interceptor-stack>
        </interceptors>
    </package>
<include file="net\xx\control\config\webwork-user.xml"/>
</xwork>

webwork-user.xml

Java代码收藏代码
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN" "http://www.opensymphony.com/xwork/xwork-1.0.dtd">
<xwork>
<package name="login" extends="webwork-default" namespace="/user">
    <action name="login" class="net.xx.control.action.SystemAction">
            <result name="success" type="dispatcher">
                <param name="location">/index.jsp</param>
            </result>
            <result name="error" type="dispatcher">
                <param name="location">/login.jsp</param>
            </result>
        <interceptor-ref name="modelParamsStack"/>
    </action>
</package>
</xwork>

web.xml

Java代码收藏代码
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
    <servlet>
        <servlet-name>webwork</servlet-name>
        <servlet-class>
            com.opensymphony.webwork.dispatcher.ServletDispatcher
        </servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/applicationContext*.xml</param-value>
        </init-param>
    <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>webwork</servlet-name>
        <url-pattern>*.action</url-pattern>
    </servlet-mapping>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext*.xml</param-value>
    </context-param>
        <filter>
        <filter-name>openSessionInViewFilter</filter-name>
        <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>openSessionInViewFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
</web-app>

在javae也搜索到类似的问题，但。。还是没解决
http://www.iteye.com/post/139291

解决了
原来默认的是根据name来注入action的service
在webwork.properties
声明一下，就行了。。。吐血。。。
webwork.objectFactory.spring.autoWire = type

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