PAT B1012 数字分类 问题:总有最后一个测试点过不去

​​​​​这个题目如果总是有个测试点过不去就是因为A2类的交错求和的结果本身就是0,而你把0作为判断这一类数字不存在的条件是错误的。

#include<cstdio>
int main(){
	int n,m;
	int a1=0,a2=0,a4=0,a3=0,a5=0;
	int count=0,count1=0;
	
	scanf("%d",&n);
	while(n--){
		scanf("%d",&m);
		if(m%5==0&&m%2==0)
		   a1+=m;
		if(m%5==1){
			if(count%2==0){
				a2+=m;
				count++;
			}
			else {
				a2+=(-1*m);
				count++;
			}
		}
		if(m%5==2)
		   a3++;
		if(m%5==3){
			 a4+=m;
			 count1++;
		}
		if(m%5==4)
		  if(m>a5)
		     a5=m;	  
	}
	if(a1==0) printf("N ");
	else printf("%d ",a1);
	if(count==0) printf("N ");
	else printf("%d ",a2);
	if(a3==0) printf("N ");
	else printf("%d ",a3);
	if(a4==0) printf("N ");
	else printf("%.1f ",(double)a4/count1);
	if(a5==0) printf("N");
	else printf("%d",a5);
	
}

 

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转载自blog.csdn.net/liujialing_lala/article/details/81170544