c语言实现字符串转换为整型

实现字符串“12345”转换为整型12345
#include<stdio.h>
#include<string.h>
int main()
{
char a[20]="12345";
int i,j;
int p=0,sum=0;
for(i=strlen(a)-1,j=1;i>=0;i--)
{
a[i]=a[i]-'0';
sum+=a[i]*j;
j=j*10;
}
printf("%d",sum);
}

猜你喜欢

转载自blog.csdn.net/hahaandhehe/article/details/79226010