poj算法-使用C语言在VC++6.0实现poj1004

poj1004:

Financial Management

题目描述：
Larry graduated this year and finally has a job. He’s making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what’s been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.
输入：
The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.
输出：
The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.
例如，输入：
100.00
489.12
12454.12
1234.10
823.05
109.20
5.27
1542.25
839.18
83.99
1295.01
1.75
输出：
$1581.42

输入十二个月的收入，最后输出其平均值。用美元符号表示。采用循环判断输入为12个月，然后将其累加。输出时将其输出为相应的$符在前的形式。

#include <stdio.h>

int main(){
    double monthmoney;
    double sum=0.0;
    int month=0;
    int i;
    for(i=1;i<=12;i++){
    scanf("%lf",&monthmoney);
    sum+=monthmoney;
    }
 printf("$%.2lf\n",sum/12);
}

代码可以在VC++6.0中正确运行，也可以在poj中正确运行。