148 Sort List(排序链表)
题目:链接
一、归并排序:
class Solution {
public:
ListNode *mergeSortList(ListNode *head)
{
if(head == NULL || head->next == NULL)
return head;
else
{ ////快慢指针找到中间节点
ListNode *fast = head, *slow = head;
while(fast->next != NULL && fast->next->next != NULL)
{
fast = fast->next->next;
slow = slow->next;
}
fast = slow;
slow = slow->next;
fast->next = NULL;
fast = mergeSortList(head); //前半段排序
slow = mergeSortList(slow); //后半段排序
return merge(fast,slow);
}
}
ListNode *merge(ListNode *head1, ListNode *head2)
{
if(head1 == NULL)
return head2;
if(head2 == NULL)
return head1;
ListNode *res, *p;
if(head1->val < head2->val)
{
res = head1;
head1 = head1->next;
}
else
{
res = head2;
head2 = head2->next;
}
p = res;
while(head1 != NULL && head2 != NULL)
{
if(head1->val < head2->val)
{
p->next = head1;
head1 = head1->next;
}
else
{
p->next = head2;
head2 = head2->next;
}
p = p->next;
}
if(head1 != NULL)
p->next = head1;
else if(head2 != NULL)
p->next = head2;
return res;
}
};