python字符串练习

 
 
判断一个字符串在另一个字符串中是否存
a="abcdergabcsgabcs"
b="abc"
sum=0
for i in range(0,len(b)):
    c=a[i:i+len(b)]
    if b in a:
        sum+=1

print('存在',sum)
双色球红球(1-33随机产生6个不重复的数),蓝球(1-13随机产生1个数)
import random
index=0
a=""
while index<6:
    r=str(random.randint(1,33))
    if len(r)==1:
        r='0'+r
    if a.find(r)==-1:
        a=a+r+','
        index+=1
    else:
        continue
b=str(random.randint(1,13))
a=a+b
print(a)
#方法二 有set集合做
a=set()
 
while len(a)<=5:
    red = int(random.randint(1,33))
    a.add(red)
a=list(a)
blue=random.randint(1,16)
a.append(blue)
print(a)


猜你喜欢

转载自blog.csdn.net/mr_li1/article/details/80566865