Educational Codeforces Round 47 (Rated for Div. 2) A.Game Shopping(水题)


题目链接:http://codeforces.com/contest/1009/problem/A

       题意是有n个物品,然后你的钱包里有m张钱,然后按顺序用你钱包里的钱去按顺序买物品,买不起的话就看下一个物品,问最后能买多少个物品。


AC代码:

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int a[1005],b[1005];
int n,m;

int main()
{
  cin>>n>>m;
  for(int i=0;i<n;i++){
    cin>>a[i];
  }
  for(int i=0;i<m;i++){
    cin>>b[i];
  }
  int num1 = 0;
  int num2 = 0;
  int sum = 0;
  while(num1 < n && num2 < m){
    if(a[num1] > b[num2]){
      num1++;
      continue;
    }
      sum++;
      num1++;
      num2++;
  }
  cout<<sum<<endl;
  return 0;
}

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转载自blog.csdn.net/charles_zaqdt/article/details/81062621