C# 构造xml格式的字符串

比如要构造这样的字符串:

<OnlineEdu>
   <head>
      <PassWord>****</PassWord>
      <ServiceCode>BS002</ServiceCode>
    </head>
    <body>
      <PeopleList>
         <PeopleInfo>
            <Idcard>3203231993052802**</Idcard>
            <AptitudeCode>0001|000101|00010102</AptitudeCode>
            <TrainType>初领</TrainType>
        </PeopleInfo >
        <PeopleInfo>
            <Idcard>3203231993052802**</Idcard>
            <AptitudeCode>0001|000101|00010103</ AptitudeCode>
            <TrainType>复审</ TrainType>
        </PeopleInfo >
      </PeopleList>
    </body>
</OnlineEdu>
这个字符串 前面 "head"的部分是固定的。我们要添加的就是Peopleinfo部分;
    string xml=string.Empty;  //定义一个空字符串
    xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"+
        "<OnlineEdu>"
        + "<head>"
        + "<PassWord>*****</PassWord>"
        + "<ServiceCode>BS002</ServiceCode>"
        + "</head>"
        + "<body>"
        + "<PeopleList>"                          
        + "</PeopleList>"
        + "</body>"
        + "</OnlineEdu>";   //把一些固定的先写好
接着选择要插入的父节点位置:这里是“Popelelist”
     XmlDocument doc = new XmlDocument();
     doc.LoadXml(xml);
     XmlNode Peoplelist = doc.SelectSingleNode("OnlineEdu/body/PeopleList");
接下来生成“Peopleinfo”节点信息
    XmlElement peopleinfo = doc.CreateElement("PeopleInfo");

    XmlElement Idcard = doc.CreateElement("Idcard");
    XmlElement AptitudeCode = doc.CreateElement("AptitudeCode");
    XmlElement TrainType = doc.CreateElement("TrainType");

    Idcard.InnerText = "123124";
    AptitudeCode.InnerText = "001|001001";
    TrainType.InnerText = "初领";

    peopleinfo.AppendChild(Idcard);
    peopleinfo.AppendChild(AptitudeCode);
    peopleinfo.AppendChild(TrainType);

再把“Peopleinfo”插入到 “Peoplelist”

    Peoplelist.AppendChild(peopleinfo);

这样就能完成插入了。

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转载自blog.csdn.net/u014472643/article/details/62426710