二叉排序树的插入算法和删除某一节点算法

二叉排序树的插入和删除某一节点
这里写图片描述

#include <iostream>
using namespace std;
typedef int KeyType;
typedef int InfoType;
typedef struct
{
    KeyType key;
    InfoType otherinfo;
}ElemType;
typedef struct BSTNode
{
    ElemType data;
    struct BSTNode *lchild,*rchild;
}BSTNode,*BST;
void InsertBST(BST &T,ElemType e)
{
    BSTNode *S;
    if(!T)
    {
        S=new BSTNode;
        S->data=e;
        S->lchild=S->rchild=NULL;
        T=S;
    }
    else if(e.key<T->data.key) InsertBST(T->lchild,e);
    else if(e.key>T->data.key) InsertBST(T->rchild,e);
}
void CreateBST(BST &T)
{
    ElemType e;
    T=NULL;
    cin>>e.key;
    for(int i=1;i<=15;i++)
    {
        InsertBST(T,e);
        cin>>e.key;
    }
}
void SearchBST(BST &T,KeyType key)
{
    if(T&&key==T->data.key) cout<<"查找成功!"<<endl;
    else if(T&&key<T->data.key) return SearchBST(T->lchild,key);
    else if(T&&key>T->data.key) return SearchBST(T->rchild,key);
    else cout<<"查找失败"<<endl;
}
void DeleteBST(BST &T,KeyType key)
{
    BST P,F,Q,S;
    P=T;F=NULL;
    while(P)
    {
        if(P->data.key==key) break;
        F=P;
        if(P->data.key>key) P=P->lchild;
        else P=P->rchild;
    }
    if(!P) return;
    Q=P;
    if((P->lchild)&&(P->rchild))
    {
        S=P->lchild;
        while(S->rchild)
        {
            Q=S;
            S=S->rchild;
        }
        P->data=S->data;
        if(Q!=P) Q->rchild=S->lchild;
        else Q->lchild=S->lchild;
        delete S;
        return;
    }
    else if(!P->rchild)
    {
        P=P->lchild;
    }
    else if(!P->lchild)
    {
      P=P->rchild;
    }
    if(!F) T=P;
    else if(Q==F->lchild) F->lchild=P;
    else F->rchild=P;
    delete Q;
}
void Show(BST T)
{
    if(T)
    {
        Show(T->lchild);
        cout<<T->data.key<<" ";
        Show(T->rchild);
    }
}
int main()
{
    BST T;
    int key1,key2;
    CreateBST(T);
    Show(T);
    cout<<endl;
    cin>>key1;
    SearchBST(T,key1);
    DeleteBST(T,14);
    Show(T);
}




猜你喜欢

转载自blog.csdn.net/qq_37486501/article/details/80948087
今日推荐