里筛选出每一人的时间最新的一条记录

-- 方法1

select a.* 
 from table1 a
 where not exists(select 1 
                  from table1 b
                  where b.name=a.name and b.gdtime>a.gdtime)

-- 方法2

select a.*
 from table1 a
 inner join
 (select name,
         max(gdtime) 'maxgdtime'
  from table1 
  group by name) b on a.name=b.name and a.gdtime=b.maxgdtime