LetCode 58. 最后一个单词的长度

static int x=[](){
    std::ios::sync_with_stdio(false);
    cin.tie(NULL);
    return 0;
}();
class Solution {
public:
    int lengthOfLastWord(string s) {
        int cur_len = 0;
        for (int i = s.length() - 1; i >= 0; i--){
            if (cur_len == 0 && s[i] == ' ')
                continue;
            else if (cur_len != 0 && s[i] == ' ')
                return cur_len;
            else
                cur_len++;
        }
        return cur_len;
    }
};

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转载自blog.csdn.net/wbb1997/article/details/81003097