递归打印1到n位数

递归打印1到n位数

Exp:



#include<iostream>
#include<string>
using namespace std;

void printNumber(string number){
	bool isbegin0 = true;
	for (int i = 0; i < number.size(); i++){
		if (isbegin0&&number[i] != '0'){
			isbegin0 = false;
		}
		if (!isbegin0){
			cout << number[i];
		}
	}
	cout << "\t";
}

void print1tonre(string number, int length, int index){
	if (index == length - 1){
		printNumber(number);
		return;
	}
	for (int i = 0; i < 10; i++){
		number[index + 1] = i + '0';
		print1tonre(number, length, index + 1);
	}
}

void print1ton(int n){
	if (n <= 0){
		return;
	}
	string number(n, '0');
	for (int i = 0; i < 10; i++){
		number[0] = i + '0';
		print1tonre(number, n, 0);

	}
}

int main(){
	int n;
	cout << "Please input a number:" ;
	while (cin >> n){
		cout << endl;
		print1ton(n);
	}
	return 0;
}

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转载自blog.csdn.net/heart_leader/article/details/80007668