通过ORM模型看python对象创建过程

简易django ORM模型如下所示:

#!/usr/bin/env python
# encoding: utf-8
"""
@version: 1.0
@author: Pis
@license: Apache Licence 
@software: PyCharm
@file: orm_test.py
@time: 2018/5/9 9:52
"""

#1
class Field(object):
    def __init__(self, name, column_type):
        self.name = name
        self.column_type = column_type

    def __str__(self):
        return '<%s:%s>' % (self.__class__.__name__, self.name)

#2
class StringField(Field):
    def __init__(self, name):
        super(StringField, self).__init__(name, 'varchar(100)')

#3
class IntegerField(Field):
    def __init__(self, name):
        super(IntegerField, self).__init__(name, 'bigint')

#4
# 下一步,就是编写最复杂的ModelMetaclass了:
class ModelMetaclass(type):
    def __new__(cls, name, bases, attrs):
        if name == 'Model':  # 排除掉对Model类的修改;
            return type.__new__(cls, name, bases, attrs)
        print('Found Model: %s' % name)
        mappings = dict()
        for k, v in attrs.items():  # 查找定义的类的所有属性,
            if isinstance(v, Field):  # 如果找到一个Field属性,
                print('Found mapping: %s ==> %s' % (k, v))
                mappings[k] = v  # 就把它保存到一个__mappings__的dict中
        for k in mappings.keys():
            attrs.pop(k)  # 同时从类属性中删除该Field属性,否则,容易造成运行时错误(实例的属性会遮盖类的同名属性);
        attrs['__mappings__'] = mappings  # 保存属性和列的映射关系
        attrs['__table__'] = name  # 假设表名和类名一致  把表名保存到__table__中
        return type.__new__(cls, name, bases, attrs)

#5
# 基类Model
class Model(dict, metaclass=ModelMetaclass):
    def __init__(self, **kw):
        super(Model, self).__init__(**kw)

    def __getattr__(self, item):  # 没有找到的属性,就在这里找
        try:
            return self[item]
        except KeyError:
            raise AttributeError(r"'Model' object has no attrs :'%s'" % item)

    def __setattr__(self, key, value):
        self[key] = value

    def save(self):
        fields = []
        params = []
        args = []
        for k, v in self.__mappings__.items():
            fields.append(v.name)
            params.append('?')
            args.append(getattr(self, k, None))
        sql = 'insert into %s (%s) values (%s)' % (self.__table__, ','.join(fields), ','.join(params))
        print('SQL: %s' % sql)
        print('ARGS: %s' % str(args))

    # 子类User

#6 # 定义类的属性到列的映射: class User(Model): id = IntegerField('id') name = StringField('username') email = StringField('email') password = StringField('password') age = IntegerField('age')
#7 if __name__ == "__main__": u = User(id=12345, name='john', email='[email protected]', password='666666', height="top") u.age = 12 u.save()

 

在代码执行过程中,在执行#7之前,首先是class的创建,在没有标明metaclass的情况下默认是由type通过__new__创建class对象,在标明了metaclass的情况下由metaclass的__new__方法创建(关于metaclass 的查找顺序上一篇给出【self,parents,local】),class创建完毕后才开始#7的执行,由于User类没有构造__new__和__init__方法,且User的父类Model继承了dict类,所以当height字段不在User的attrs时依然不会报错,实际上输入任何的关键字参数都不会出错。ORM模型在u.save()时,是通过查找在__new__时__map__中的字段,也就是#6中的(id,name,email,password,age),通过sql语句动态的执行存储操作。

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转载自www.cnblogs.com/MY0213/p/9012807.html