[LeetCode]第十三题 :移除相同的值

题目描述:

Given a sorted linked list, delete all duplicates such that each element appear only once.

Example 1:

Input: 1->1->2
Output: 1->2

Example 2:

Input: 1->1->2->3->3
Output: 1->2->3

题目解释:

给出一组排好序的链表,删除所有重复元素保证每个元素只出现一次。

题目解法:

1.我的解法。首先新建一个工作指针work;然后循环遍历整个链表,先判断下一个节点是否为空,当下一节点不为空且当前节点的值和下一个节点的值相同时,当前节点的下一节点指向下一节点的下一节点;否则工作指针后移。

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        ListNode work = head;
        while(work != null){
            ListNode temp = work.next;
            if(temp != null && work.val == work.next.val) {
                work.next = temp.next;
            } else {
                work = work.next;
            }
        }
        return head;
    }
}

猜你喜欢

转载自blog.csdn.net/woaily1346/article/details/80837925