1.要求：
| 使用传参的方法写个脚本，实现加减乘除的功能。 例如： sh a.sh 1 2， 这样会分别计算加、减、乘、除的结果。 1 脚本需判断提供的两个数字必须为整数 2 当做减法或者除法时，需要判断哪个数字大 3 减法时需要用大的数字减小的数字 4 除法时需要用大的数字除以小的数字，并且结果需要保留两个小数点 |
2.脚本答案：
[root@liang 2018-06-22]# cat operation.sh #!/bin/bash if [ $# -ne 2 ];then echo "Error:Please enter two Numbers!" exit 1 fi Num1=`echo $1|sed 's/[0-9]//g'` Num2=`echo $2|sed 's/[0-9]//g'` Null= if [ "$Num1" != "$Null" ];then echo "Errpr:Please enter an integer $1 " exit 2 fi if [ "$Num2" != "$Null" ];then echo "Errpr:Please enter an integer $2 " exit 3 fi #jiafa ((add=$1+$2)) echo "${1} + ${2} = ${add}" #chengfa ((take=$1*$2)) echo "${1} * ${2} = ${take}" if [ $1 -gt $2 ];then #jianfa ((subtract=$1-$2)) echo "${1} - ${2} = ${subtract}" #chufa divide=`echo "scale=2; ${1}/${2}" | bc` echo "${1} / ${2} = ${divide}" else #jianfa ((subtract=$2-$1)) echo "${2} - ${1} = ${subtract}" #chufa divide=`echo "scale=2; ${2}/${1}" | bc` echo "${2} / ${1} = ${divide}" fi |
3.测试：
| [root@liang 2018-06-22]# bash operation.sh 1 1 1 Error:Please enter two Numbers! [root@liang 2018-06-22]# bash operation.sh a 1 Error:Please enter an integer a [root@liang 2018-06-22]# bash operation.sh 1 b Error:Please enter an integer b [root@liang 2018-06-22]# bash operation.sh 5 11 5 + 11 = 16 5 * 11 = 55 11 - 5 = 6 11 / 5 = 2.20 [root@liang 2018-06-22]# bash operation.sh 11 5 11 + 5 = 16 11 * 5 = 55 11 - 5 = 6 11 / 5 = 2.20 |