AJAX406的问题

今天帮朋友改一个代码,前台一直报406  进network里看的时候

显示如下



问题大概清楚了,结尾是伪.html,方法的mapping也是html  代码太乱,不想看

	@RequestMapping(value = "modif.html", method = RequestMethod.POST) // 第二级URL
	public @ResponseBody Map<String, Object> modiyQuestion(@RequestBody Question question) {
		Map<String, Object> result = null;
		if (!question.getModifyid().equals("")) {
			switch (question.getModifypoint()) {
			case "XZT":
				// 搜索前台传入id,并从数据库取出具体数据
				SelectionQuestion selectionQuestion = selectionQuestionService
						.searchSelectionQuestionById(Integer.parseInt(question.getModifyid()));
				if (selectionQuestion != null) {
					// 把查询到的数据返回给前台
					result = new HashMap<String, Object>();
					result.put("msg", selectionQuestion);
					result.put("classes", "XZT");
				}
				return result;
			case "TKT":
				FillQuestion fillQuestion = fillQuestionService
						.searchFillQuestionById(Integer.parseInt(question.getModifyid()));
				if (fillQuestion != null) {
					result = new HashMap<String, Object>();
					result.put("msg", fillQuestion);
					result.put("classes", "TKT");
				}
				return result;

			case "PDT":
				JudgementQuestion judgementQuestion = judgementQuestionService
						.searchJudgementQuestionById(Integer.parseInt(question.getModifyid()));
				if (judgementQuestion != null) {
					result = new HashMap<String, Object>();
					result.put("msg", judgementQuestion);
					result.put("classes", "PDT");
				}
				return result;
			case "WDT":
				EssayQuestion essayQuestion = essayQuestionService
						.searchEssayQuestionById(Integer.parseInt(question.getModifyid()));
				if (essayQuestion != null) {
					result = new HashMap<String, Object>();
					result.put("msg", essayQuestion);
					result.put("classes", "WDT");
				}
				return result;
			default:
				System.out.println("匹配出错");
				break;
			}
		}

		return result;
	}

解决方案:在入口处增加*.json的访问方式

	<servlet-mapping>
		<servlet-name>seckill-dispatcher</servlet-name>
		<url-pattern>*.html</url-pattern>
	</servlet-mapping>
		<servlet-mapping>
		<servlet-name>seckill-dispatcher</servlet-name>
		<url-pattern>*.json</url-pattern>
	</servlet-mapping>

将url和mapping都改为.json

重启服务,


成功进入success回调方法。完

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转载自blog.csdn.net/weixin_41809916/article/details/79941098