redis发布-订阅

PUBLISH

PUBLISH channel message

将信息 message 发送到指定的频道 channel 。

可用版本:

>= 2.0.0

时间复杂度:

O(N+M),其中 N 是频道 channel 的订阅者数量,而 M 则是使用模式订阅(subscribed patterns)的客户端的数量。

返回值:

接收到信息 message 的订阅者数量。 

例子

# 对没有订阅者的频道发送信息

redis> publish bad_channel "can any body hear me?"
(integer) 0


# 向有一个订阅者的频道发送信息

redis> publish msg "good morning"
(integer) 1


# 向有多个订阅者的频道发送信息

redis> publish chat_room "hello~ everyone"
(integer) 3

SUBSCRIBE

SUBSCRIBE channel [channel ...]

订阅给定的一个或多个频道的信息。

可用版本:

>= 2.0.0

时间复杂度:

O(N),其中 N 是订阅的频道的数量。

返回值:

接收到的信息(请参见下面的代码说明)。 

例子

# 订阅 msg 和 chat_room 两个频道

# 1 - 6 行是执行 subscribe 之后的反馈信息
# 第 7 - 9 行才是接收到的第一条信息
# 第 10 - 12 行是第二条

redis> subscribe msg chat_room
Reading messages... (press Ctrl-C to quit)
1) "subscribe"       # 返回值的类型:显示订阅成功
2) "msg"             # 订阅的频道名字
3) (integer) 1       # 目前已订阅的频道数量

1) "subscribe"
2) "chat_room"
3) (integer) 2

1) "message"         # 返回值的类型:信息
2) "msg"             # 来源(从那个频道发送过来)
3) "hello moto"      # 信息内容

1) "message"
2) "chat_room"
3) "testing...haha"

golang示例1


package main

import (
    "log"

    "github.com/garyburd/redigo/redis"
)



func main() {

    server := "10.194.80.35:6379"

    option := redis.DialPassword("123456")
    c, err := redis.Dial("tcp", server, option)
    if err != nil {
        log.Println("connect server failed:", err)
        return
    }

    defer c.Close()

    c.Send("SUBSCRIBE", "TongTianDaDao")
    c.Flush()
    for {
        reply, err := redis.Values(c.Receive())
        if err != nil {
            log.Println("Receive failed:", err)
        }
        
        log.Println("reply:", reply)
    
        for i,v := range reply {

            switch vv:= v.(type){
            case int64:
                log.Println(i,":", vv)
            case []byte:
                log.Println(i,":", string(vv))
            case string:
                log.Println(i,":", vv)
            default:
                log.Println("unknown:",v)
            }

        }
    }


}

output:

2018/06/29 14:26:30 reply: [[115 117 98 115 99 114 105 98 101] [84 111 110 103 84 105 97 110 68 97 68 97 111] 1]
2018/06/29 14:26:30 0 : subscribe
2018/06/29 14:26:30 1 : TongTianDaDao
2018/06/29 14:26:30 2 : 1
2018/06/29 14:27:22 reply: [[109 101 115 115 97 103 101] [84 111 110 103 84 105 97 110 68 97 68 97 111] [111 110 101 32 114 111 97 100]]
2018/06/29 14:27:22 0 : message
2018/06/29 14:27:22 1 : TongTianDaDao
2018/06/29 14:27:22 2 : one road
2018/06/29 14:28:04 reply: [[109 101 115 115 97 103 101] [84 111 110 103 84 105 97 110 68 97 68 97 111] [116 119 111 32 114 111 97 100 115]]
2018/06/29 14:28:04 0 : message
2018/06/29 14:28:04 1 : TongTianDaDao
2018/06/29 14:28:04 2 : two roads

golang示例2

使用库包裹函数


package main

import (
    "log"

    "github.com/garyburd/redigo/redis"
)



func main() {

    server := "10.194.80.35:6379"

    option := redis.DialPassword("123456")
    c, err := redis.Dial("tcp", server, option)
    if err != nil {
        log.Println("connect server failed:", err)
        return
    }

    defer c.Close()

    psc := redis.PubSubConn{Conn:c}
    psc.Subscribe("TongTianDaDao")
    
    for {
        switch v := psc.Receive().(type) {
        case redis.Message:
            log.Printf("%s: message: %s\n", v.Channel, v.Data)
        case redis.Subscription:
            log.Printf("%s: %s %d\n", v.Channel, v.Kind, v.Count)
        case error:
            log.Println("Receivd failed:", v)
        }
    }

}

output:

2018/06/29 14:37:09 TongTianDaDao: subscribe 1
2018/06/29 14:37:18 TongTianDaDao: message: one road
2018/06/29 14:37:20 TongTianDaDao: message: two roads

参考

https://github.com/gomodule/redigo

https://godoc.org/github.com/gomodule/redigo/redis

http://redisdoc.com/

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转载自www.cnblogs.com/lanyangsh/p/9243439.html