JavaScript - 代码片段，Snippets，Gist

求n个数字的累加和

1. 递归实现

   function getSum(x) {
     if (x == 1) {
       return 1;
     }
     return x + getSum(x - 1);
   }
   
   var result = getSum(100);
   console.log(result);

求一个数字的每个位数上的和 :如:23--->5

1. 递归实现

   function getnumberSum(x) {
     if (x < 10) {
       return x;
     }
     return parseInt(x % 10 + getnumberSum(x / 10));
   }
   console.log(getnumberSum(123));