静态通讯录的实现

实现一个通讯录；
通讯录可以用来存储1000个人的信息，每个人的信息包括：
姓名、性别、年龄、电话、住址

提供方法：
1. 添加联系人信息
2. 删除指定联系人信息
3. 查找指定联系人信息
4. 修改指定联系人信息
5. 显示所有联系人信息
6. 清空所有联系人

7. 以名字排序所有联系人

经过多次调试，代码初成：

#ifndef CONTACT_H
#define CONTACT_H
#endif



#include<stdio.h>
#include<windows.h>
#include<stdlib.h>
#pragma warning(disable:4996)

#define NAME_MUN  20
#define SEX_NUM  5
#define TEL_NUM  11
#define ADDR_NUM  30
#define MAX   1000
struct tellphone
{
	char name[NAME_MUN];
	char sex[SEX_NUM];
	int age;
	char tel[TEL_NUM];
	char addr[ADDR_NUM];
};
typedef struct contact
{
	struct tellphone people[MAX];
	int count;
}ps;



void add_contact(ps* pcon);
void del_contact(ps* pcon);
int search_contact(ps* pcon);
void change_contact(ps* pcon);
void show_contact(ps* pcon);
void inti_contact(ps* pcon);
void sort_contact(ps* pcon);

#include"contact.h"
void add_contact(ps* pcon)//增加
{
	if (pcon->count == MAX)
	{
		printf("通讯录满了\n");
		return ;
	}
	else
	{
		printf("输入姓名：");
		scanf("%s", pcon->people[pcon->count].name);
		printf("输入性别:");
		scanf("%s", pcon->people[pcon->count].sex);
		printf("输入年龄:");
		scanf("%d", &pcon->people[pcon->count].age);
		printf("输入电话:");
		scanf("%s", pcon->people[pcon->count].tel);
		printf("输入地址:");
		scanf("%s", pcon->people[pcon->count].addr);
		pcon->count++;
	}
	return 0;
}
void del_contact(ps* pcon)//删除
{
	int i;
	int ret = search_contact(pcon);
	if (ret != -1)
	{
		for (i = ret;i < pcon->count-1;i++)
		{
			pcon->people[i] = pcon->people[i + 1];
		}
		pcon->count--;
	}
	else
	{
		printf("没有");
		return -1;
	}
}
int search_contact(ps* pcon)//寻找
{
	int i;
	char name[20];
	printf("请输入名字:");
	scanf("%s", name);
	for (i = 0;i < pcon->count;i++)
	{
		if (strcmp(pcon->people[i].name, name) == 0)
		{
			printf("name  sex  age  tel  addr\n");
			printf("%s  ", pcon->people[i].name);
			printf("%d  ", pcon->people[i].age);
			printf("%s  ", pcon->people[i].tel);
			printf("%s  ", pcon->people[i].addr);
			printf("\n");
			return i;
		}
	}
	printf("没有");
	return -1;
}
void change_contact(ps* pcon)//改名
{
	int ret = search_contact(pcon);
	if (ret != -1)
	{
		printf("输入姓名:");
		scanf("%s", pcon->people[ret].name);
		printf("输入性别:");
		scanf("%s", pcon->people[ret].sex);
		printf("输入年龄:");
		scanf("%d", &pcon->people[ret].age);
		printf("输入电话:");
		scanf("%s", pcon->people[ret].tel);
		printf("输入地址:");
		scanf("%s", pcon->people[ret].addr);
		return;
	}
	printf("输入错误");
	return -1;
}void show_contact(ps* pcon)
//显示
{
	int i;
	printf("name  sex  age  tel  addr\n");
	for (i = 0;i < pcon->count;i++)
	{
	    printf("%s  ", pcon->people[i].name);
		printf("%s  ", pcon->people[i].sex);
		printf("%d  ", pcon->people[i].age);
		printf("%s  ", pcon->people[i].tel);
		printf("%s  ", pcon->people[i].addr);
		printf("\n");
	}
	return;
}

void inti_contact(ps* pcon)//初始化
{
	pcon->count = 0;
}
void sort_contact(ps* pcon)//排序
{
	int i;
	int j;
	for (i = 0;i < pcon->count - 1;i++)
	{
		for (j = 0;j < pcon->count - 1 - i;j++)
		{
			if (strcmp(pcon->people[j].name, pcon->people[j + 1].name) > 0)
			{
				char temp[20];
				strcpy(temp, pcon->people[j].name);
				strcpy(pcon->people[j].name, pcon->people[j+1].name);
				strcpy(pcon->people[j+1].name,temp);
			}
		}
	}
	show_contact(pcon);
}

#include"contact.h"
void menu()
{
	printf("#######################\n");
	printf("##1.add         2.del##\n");
	printf("##3.search   4.change##\n");
	printf("##5.show       6.inti##\n");
	printf("##7.sort       8.exit##\n");
	printf("#######################\n");
}
int main()
{
	int n;
	struct contact people;
	people.count = 0;
	while (1)
	{
		menu();
		printf("please input one number:");
		scanf("%d", &n);
		switch (n)
		{
		case 1:
			add_contact(&people);
			break;
		case 2:
			del_contact(&people);
			break;
		case 3:
			search_contact(&people);
			break;
		case 4:
			change_contact(&people);
			break;
		case 5:
			show_contact(&people);
			break;
		case 6:
			inti_contact(&people);
			break;
		case 7:
			sort_contact(&people);
			break;
		case 8:
			exit(0);
		default:
			printf("input error\n");
			break;
		}
	}
	system("pause");
	return 0;
}

结果如下：

菜鸟一枚，能力有限，反复演示，已证无误！

上图只为大家演示了添加和排序过程，演示过程不够清晰，还请大家谅解！不说了，不说了，舍友叫我打游戏呢！

静态通讯录的实现

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