数据库考试内容（MYSQL）

附（答案）

1）插入记录

INSERT student (sid,sname,sex,birth,classes) VALUE (1001,"张三",1,"1998-7-1",1801) ;

2）修改姓名为张三的学生班级

UPDATE student SET classes = 1802 WHERE sname LIKE "张三" ;

3）删除记录（张三and 1802）

DELETE FROM student WHERE sname = "张三" AND classes = 1802 ;

4）查询student所有记录

SELECT * FROM student ;

5）查询student表中1803班的学生信息

SELECT * FROM student WHERE classes = 1803 ;

6）查询student表中学号为1003，1006，1009的学生信息

SELECT * FROM student WHERE sid = 1003 OR sid = 1006 OR sid = 1009 ;

7）查询score表中课程号为1 成绩大于80分的学号

SELECT sid FROM score  WHERE  co_id = 1 AND grade>80 ;

8）分别统计student表中男女生数量 备注：1为男 0为女

SELECT sex AS '性别',COUNT(*) AS '数量' FROM student GROUP BY sex

9）查询平均成绩大于60分的学生的学号和平均成绩，并根据成绩倒叙显示

SELECT sid AS '学号',AVG(grade) AS '平均成绩' FROM score GROUP BY sid HAVING AVG(grade)>80 ORDER BY AVG(grade) DESC

10）通过表连接查询出学生的姓名、课程名及成绩

SELECT sname,grade,cname FROM student JOIN score JOIN course ON score.`sid`=student.`sid` AND score.`co_id` = course.`co_id`