栈及其应用

Written by Robert_Wang in Southwest University of Science And Technology.

#include<iostream>
#define MaxSize 100 
using namespace std;
typedef char ElemType;
typedef struct
{
	ElemType data[MaxSize];
	int top;
}SqStack;
typedef struct LinkNode
{
	ElemType data;
	struct LinkNode *next;
}LinkStack;
void InitStack(SqStack *&s)
{
	s = new SqStack;
	s->top = -1;
}
void InitStack(LinkStack *&s)
{
	s = new LinkStack;
	s->next = NULL;
}
void DestroyStack(SqStack *&s)
{
	delete s;
}
void DestroyStack(LinkStack *&s)
{
	LinkStack *p, *pre;
	pre = s;
	p = s->next;
	while (p)
	{
		delete pre;
		pre = p;
		p = p->next;
	}
	delete pre;
}
bool StackEmpty(SqStack *&s)
{
	return s->top == -1;
}
bool StackEmpty(LinkStack *&s)
{
	return s->next == NULL;
}
bool Push(SqStack *& s, ElemType e)
{
	if (s->top == MaxSize-1) return false;
	s->data[++s->top] = e;
	return true;
}
void Push(LinkStack *&s, ElemType& e)
{
	LinkStack *p = new LinkStack;
	p->data = e;
	p->next = s->next;
	s->next = p;
}
bool Pop(SqStack *&s, ElemType &e)
{
	if (StackEmpty(s)) return false;
	e = s->data[s->top--];
	return true;
}
bool Pop(LinkStack *&s, ElemType &e)
{
	if (StackEmpty(s)) return false;
	e = s->next->data;
	LinkStack *p = s->next;
	s->next = p->next;
	delete p;
	return true;
}
bool GetTop(SqStack*s, ElemType& e)
{
	if (StackEmpty(s)) return false;
	e = s->data[s->top];
	return true;
}
bool GetTop(LinkStack*s, ElemType& e)
{
	if (StackEmpty(s)) return false;
	e = s->next->data;
	return true;
}
//中缀表达式变为后缀表达式
void trans(char *exp, char postexp[])
{
	char e;
	int i = 0;
	SqStack *s;
	InitStack(s);
	while (*exp)
	{
		switch (*exp)
		{
		case '(': Push(s, *exp); exp++; break;
		case ')':
			Pop(s, e);
			while (e != '(')
			{
				postexp[i++] = e;
				Pop(s, e);
			}
			exp++;
			break;
		case '+':
		case '-':
			while (!StackEmpty(s))
			{
				GetTop(s, e);
				if (e !='(')//将 ( 和 +之间包括+ 存入postexp
				{
					postexp[i++] = e;
					Pop(s, e);
				}
				else break;	
			}
			Push(s, *exp);//
			exp++;
			break;
		case '*':
		case '/':
			while (!StackEmpty(s))
			{
				GetTop(s, e);
				if (e == '*' || e == '/')
				{
					postexp[i++] = e;
					Pop(s, e);
				}
				else break;
			}
			Push(s, *exp);
			exp++;
			break;
		default:
			while (*exp >= '0' && *exp <= '9')
			{
				postexp[i++] = *exp;
				exp++;
			}
			postexp[i++] = '#';
		}
	}
	while (!StackEmpty(s))
	{
		Pop(s, e);
		postexp[i++] = e;
	}
	postexp[i] = '\0';
	DestroyStack(s);
}
double compvalue(char *postexp)
{
	char a,b,c,d,e;
	SqStack *s;
	InitStack(s);
	while (*postexp != '\0')
	{
		switch (*postexp)
		{
		case '+':Pop(s, a); Pop(s, b); 
			e = a + b;
			Push(s, e); break;
		case '-':Pop(s, a); Pop(s, b);
			e = b-a;
			Push(s, e); break;
		case '*':Pop(s, a); Pop(s, b);
			e = a * b; 
			Push(s, e); break;
		case '/':Pop(s, a); Pop(s, b);
			if (!a) {
				cout << "除0错误" << endl;
				exit(0);//异常退出
			}
			else
			{
				e = b / a;
				Push(s, e);
				break;
			}
		default://将连续的数字转化为对应的数字
			d = 0;
			while (*postexp >= '0' && *postexp <= '9')
			{
				d = 10 * d + *postexp - '0';//int char操作时,会自动转化为int ,如'9'+2 = 11;然后又转化为char 
				postexp++;
			}
			Push(s, d);
			break;
		}
		postexp++;
	}
		GetTop(s, e);
		DestroyStack(s);
	return 	e;
}
int main()
{
	
	char s[100] = "(56-20)/(4+2)", s1[100];
	trans(s, s1);
	cout << "中缀表达式为:"<<s << endl;
	cout << "后缀表达式"<<s1 << endl;
	cout << "表达式的值为:" << compvalue(s1) << endl;
	return 0;
}

猜你喜欢

转载自blog.csdn.net/qq_40883132/article/details/79464228