原生的ajax,get post请求需要注意的地方

1.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>无标题文档</title>
<script>
    window.onload = function(){
        var btn = document.getElementById('btn');
        btn.onclick = function(){
            var xhr = null;
            try{
                xhr = new XMLHttpRequest();
            }catch(e){
                xhr = new ActiveXObject('Microsoft.XMLHTTP');
            }
            /*
            get 方式请求数据,1:缓存,解决方法:加上时间戳
                            2: 中文,采用ecodeURI
            但在最新的浏览器中均不需要
            xhr.open('get','2_get.php?username='+encodeURI('刘伟')+'&age=20&'+new Date().getTime(),true);
            xhr.send();
            */
             
            /*post 方式请求数据,数据放的位置不同*/
            xhr.open('post','2_get.php',true);
            xhr.setRequestHeader('content-type','application/x-www-form-urlencoded');
            xhr.send('username=leo&age=20');
             
            
            xhr.onreadystatechange = function(){
                if(xhr.readyState == 4){
                    alert(xhr.responseText);
                }
            }
            
        };
    };
</script>
</head>

<body>
<input type="button" value="按钮" id="btn"/>
</body>
</html>
<?php
    header('content-type:text/html; charset="utf-8"');
    error_reporting(0);
    
//    $username = $_GET['username'];
//    $age = $_GET['age'];

    $username = $_POST['username'];
    $age = $_POST['age'];
    
    echo "欢迎,你的名字:{$username},年龄:{$age}";
 
 
 
 

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转载自www.cnblogs.com/moon-yyl/p/9210778.html