使用SQL语句查询每门课程都大于80分的学生姓名

创建表

create table stu_grade(name varchar(20),course varchar(20),grade int);

插入数据

INSERT INTO stu_grade VALUES ('张三', '语文', '81');
INSERT INTO stu_grade VALUES ('张三', '数学', '75');
INSERT INTO stu_grade VALUES ('李四', '语文', '76');
INSERT INTO stu_grade VALUES ('李四', '数学', '90');
INSERT INTO stu_grade VALUES ('王五', '语文', '81');
INSERT INTO stu_grade VALUES ('王五', '数学', '100');
INSERT INTO stu_grade VALUES ('王五', '英语', '90');

题1:使用SQL语句查询每门课程都大于80分的学生姓名

方法一:

select name from stu_grade group by name having MIN(grade)>80

方法二:

select distinct name from stu_grade where name not in (select distinct name from stu_grade where grade <=80)

 题2:使用SQL语句查询每门课程和大于240分的学生姓名

select name from stu_grade group by having SUM(grade)>240

提3:mysql取出stu_grade中的3到7行

select * from stu_grade limit 3,7;

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转载自blog.csdn.net/weixin_45467975/article/details/130083300