CodeMonkey过关学习笔记系列:129-135关

CodeMonkey过关学习笔记系列:129-135关

•”布尔逻辑” 歌剧( BOOLEAN OPERA ) 120~135

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129 关挑战

until tiger.sleeping() or tiger.playing()
    wait()
goto banana

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130 关挑战

或者 or 指令能够让小猴等到许多个判断式其中之一的条件成立了之后,就开始下个行动.
until tiger.sleeping() or tiger.playing()
    wait()
goto banana



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131 关挑战

//你可以在所有的判断式里面都使用 或者 or 指令
until tiger.sleeping() or tiger.playing()
    wait()

step 10

//#这里等待 <code>wait</code> 熊玩耍或睡着
until bear.sleeping() or bear.playing()
    wait()
step 10

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132 关挑战

until bear.playing() or bear.sleeping()
    wait()

goat.goto banana

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133 关挑战
for b in bananas
    until tiger.playing() or tiger.sleeping()
        wait()
    if b.green()
        goat.goto b
    else
        monkey.goto b


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134 关挑战
for b in bears
    until b.sleeping() or b.playing()
        wait()
    step 10

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135 关挑战

waitFor = (t) ->
    until t.sleeping() or t.playing()
        wait()

for t in tigers
    for stepper in [monkey, goat]
        waitFor t
        stepper.step 10


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转载自blog.csdn.net/mmh19891113/article/details/80758612