CodeMonkey过关学习笔记系列:129-135关
•”布尔逻辑” 歌剧( BOOLEAN OPERA ) 120~135
第 129 关挑战
until tiger.sleeping() or tiger.playing()
wait()
goto banana
第 130 关挑战
或者 or 指令能够让小猴等到许多个判断式其中之一的条件成立了之后,就开始下个行动.
until tiger.sleeping() or tiger.playing()
wait()
goto banana
第 131 关挑战
//你可以在所有的判断式里面都使用 或者 or 指令
until tiger.sleeping() or tiger.playing()
wait()
step 10
//#这里等待 <code>wait</code> 熊玩耍或睡着
until bear.sleeping() or bear.playing()
wait()
step 10
第 132 关挑战
until bear.playing() or bear.sleeping()
wait()
goat.goto banana
第 133 关挑战
for b in bananas
until tiger.playing() or tiger.sleeping()
wait()
if b.green()
goat.goto b
else
monkey.goto b
第 134 关挑战
for b in bears
until b.sleeping() or b.playing()
wait()
step 10
第 135 关挑战
waitFor = (t) ->
until t.sleeping() or t.playing()
wait()
for t in tigers
for stepper in [monkey, goat]
waitFor t
stepper.step 10