字符串替换升级版(不用考虑两个字符串的长度)

把字符串s换为st (s-->st)

code:

#include<bits/stdc++.h>  
using namespace std;  
char s[1005]="scanf" ; 
char st[1005]="printf"; 
char store[1005];  
int main()  
{  
    char a[100005];
    while(gets(a))
    {  
        //memset(store,0,sizeof(store));  
        int p;  
        int pos;  
        int l=strlen(a);  
        int i,j;  
        for(i=0;i<l;i++)  
        {  
            p=0;  
            if(a[i]=='s')//查找st的第一个字符 
            {  
                pos=i;  
                for(j=pos;j<=strlen(s)-1+pos;j++)  
                {  
                    store[p]=a[j];  
                    p++;  
                }  
            }  
            
            if(strcmp(store,s)==0)  
            {  
                cout<<st;  
                i+=(strlen(s)-1);  
            }  
			else   
            {  
                cout<<a[i];  
            }  
            
			memset(store,0,sizeof(store));
        }  
        cout<<endl;  
    }  
    return 0;  
 } //把s替换为st s-->st 


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转载自blog.csdn.net/qq_41333844/article/details/80670746