python获取文件夹

获取指定文件夹下面所有文件路径以及含文件的子文件夹路径


import os

def read_files(directory):
    for root, dirs, files in os.walk(directory):
        for file_name in files:
            file_path = os.path.join(root, file_name)
            parent_directory = os.path.dirname(root)  # Get the parent directory
            
           
# Specify the directory path
directory_path = '/path/to/directory'

# Call the function to read files from the directory and its subdirectories
read_files(directory_path)

如果需要将结果返回,可以采用一个集合的形式将获取到的文件路径和文件夹路径放到一起返回

import os

def read_files(directory):
    result = set()  # 创建一个空的集合
    
    for root, dirs, files in os.walk(directory):
        for file_name in files:
            file_path = os.path.join(root, file_name)
            parent_directory = os.path.dirname(root)  # 获取父目录路径
            
            # 将 file_path 和 parent_directory 添加到集合中
            result.add((file_path, parent_directory))
            
    return result

# 指定目录路径
directory_path = '/path/to/directory'

# 调用函数读取目录及其子目录中的文件,并获取结果集合
file_info_set = read_files(directory_path)

# 打印结果集合
for file_path, parent_directory in file_info_set:
    print("File Path:", file_path)
    print("Parent Directory:", parent_directory)
    print()  # 打印空行,用于分隔每个文件的信息

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转载自blog.csdn.net/biyn9/article/details/130977856