一、说明

做你还记得小时候玩井字游戏吗？这是一个简单的游戏，只需一支笔或铅笔就可以在一张纸上玩。但是你知道你也可以使用Python的Tkinter库创建一个井字游戏吗？在本文中，我们将介绍使用 Tkinter 创建井字游戏的过程。在本文结束时，您将对如何使用 GUI 框架创建简单游戏有一个基本的了解，并且您将与您的朋友和家人一起玩一个有趣的游戏！

二、导入库和模块：

import tkinter as tk
from tkinter import messagebox

代码首先导入所需的模块和库，即和模块，这些模块和库是创建用户界面和消息提示所必需的。tkintermessagebox

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三、创建窗口和看板：

window = tk.Tk()
window.title("Tic Tac Toe")

# Create board
def create_board():
    for i in range(3):
        for j in range(3):
            button = tk.Button(window, text="", font=("Arial", 50), height=2, width=6, bg="lightblue", command=lambda row=i, col=j: handle_click(row, col))
            button.grid(row=i, column=j, sticky="nsew")

create_board()

该函数用于创建游戏的主窗口。该函数用于使用该方法创建 3x3 井字棋板。tk.Tk()create_board()tk.Button()

四、初始化变量：

# Initialize variables
board = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
current_player = 1

初始化游戏变量，包括存储游戏板状态的列表和跟踪当前玩家的变量。boardcurrent_player

五、处理按钮点击

# Handle button clicks
def handle_click(row, col):
    global current_player

    if board[row][col] == 0:
        if current_player == 1:
            board[row][col] = "X"
            current_player = 2
        else:
            board[row][col] = "O"
            current_player = 1

        button = window.grid_slaves(row=row, column=col)[0]
        button.config(text=board[row][col])

        check_for_winner()

每当单击游戏板上的按钮时，都会调用该函数。它使用当前玩家的移动更新游戏板，将当前玩家更改为下一个玩家，并相应地更新按钮文本。handle_click()

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六、检查获胜者或平局

def check_for_winner():
    winner = None

    # Check rows
    for row in board:
        if row.count(row[0]) == len(row) and row[0] != 0:
            winner = row[0]
            break

    # Check columns
    for col in range(len(board)):
        if board[0][col] == board[1][col] == board[2][col] and board[0][col] != 0:
            winner = board[0][col]
            break

    # Check diagonals
    if board[0][0] == board[1][1] == board[2][2] and board[0][0] != 0:
        winner = board[0][0]
    elif board[0][2] == board[1][1] == board[2][0] and board[0][2] != 0:
        winner = board[0][2]

    if all([all(row) for row in board]) and winner is None:
        winner = "tie"

    if winner:
        declare_winner(winner)

每次单击按钮后都会调用该函数以检查是否有获胜者或平局。它会检查游戏板上的获胜组合，包括行、列和对角线，如果未找到获胜者，则返回获胜者或“平局”。check_for_winner()

七、宣布获胜者并重新开始游戏：

def declare_winner(winner):
    if winner == "tie":
        message = "It's a tie!"
    else:
        message = f"Player {winner} wins!"


    answer = messagebox.askyesno("Game Over", message + " Do you want to restart the game?")

    if answer:
        global board
        board = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]

        for i in range(3):
            for j in range(3):
                button = window.grid_slaves(row=i, column=j)[0]
                button.config(text="")

        global current_player
        current_player = 1
    else:
        window.quit()

八、运行游戏：

window.mainloop()

调用该函数以启动游戏并运行窗口，直到用户关闭窗口或结束游戏。window.mainloop()

九、完整代码：

import tkinter as tk
from tkinter import messagebox

window = tk.Tk()
window.title("Tic Tac Toe")

# Create board
def create_board():
    for i in range(3):
        for j in range(3):
            button = tk.Button(window, text="", font=("Arial", 50), height=2, width=6, bg="lightblue", command=lambda row=i, col=j: handle_click(row, col))
            button.grid(row=i, column=j, sticky="nsew")

create_board()

# Initialize variables
board = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
current_player = 1

# Handle button clicks
def handle_click(row, col):
    global current_player

    if board[row][col] == 0:
        if current_player == 1:
            board[row][col] = "X"
            current_player = 2
        else:
            board[row][col] = "O"
            current_player = 1

        button = window.grid_slaves(row=row, column=col)[0]
        button.config(text=board[row][col])

        check_for_winner()

# Check for a winner or a tie
def check_for_winner():
    winner = None

    # Check rows
    for row in board:
        if row.count(row[0]) == len(row) and row[0] != 0:
            winner = row[0]
            break

    # Check columns
    for col in range(len(board)):
        if board[0][col] == board[1][col] == board[2][col] and board[0][col] != 0:
            winner = board[0][col]
            break

    # Check diagonals
    if board[0][0] == board[1][1] == board[2][2] and board[0][0] != 0:
        winner = board[0][0]
    elif board[0][2] == board[1][1] == board[2][0] and board[0][2] != 0:
        winner = board[0][2]

    if all([all(row) for row in board]) and winner is None:
        winner = "tie"

    if winner:
        declare_winner(winner)

# Declare the winner and ask to restart the game
def declare_winner(winner):
    if winner == "tie":
        message = "It's a tie!"
    else:
        message = f"Player {winner} wins!"


    answer = messagebox.askyesno("Game Over", message + " Do you want to restart the game?")

    if answer:
        global board
        board = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]

        for i in range(3):
            for j in range(3):
                button = window.grid_slaves(row=i, column=j)[0]
                button.config(text="")

        global current_player
        current_player = 1
    else:
        window.quit()

window.mainloop()

十、结果

十一、结论

总之，我们已经看到了如何使用Python和Tkinter库创建一个简单的井字游戏。我们首先使用 Tkinter 按钮创建游戏板，然后添加处理按钮单击、检查获胜者或平局以及宣布获胜者的功能。在此过程中，我们还学习了一些有用的 Tkinter 函数，例如 grid（）和 grid_slaves（）。按照本文中概述的步骤，您可以根据自己的喜好自定义游戏并创建自己的井字游戏版本。请记住尝试不同的颜色、字体和动画，以使游戏更加有趣和引人入胜。阿拉法特伊斯兰教

使用 Tkinter 在 Python 中构建井字游戏！