js 过滤两个数组中对象相同的项

一、案例 

  let allSaleAttr = [
    {
      id: 1,
      name: "颜色",
    },
    {
      id: 2,
      name: "版本",
    },
    {
      id: 3,
      name: "尺码",
    },
  ];
  let saleAttr = [
    {
      id: 9,
      s_Id: 5,
      saleName: "颜色",
      ValueList: [],
    },
    {
      id: 10,
      s_Id: 5,
      saleName: "版本",
      ValueList: [],
    },
  ];
//map和filter
  let saleAttrIdx = saleAttr.map(item => item.saleName);
  const result = allSaleAttr.filter(item => !saleAttrIdx.includes(item.name));
  console.log(result);

//filter和every
  function fn(allSaleAttr,saleAttr) {
    let res = allSaleAttr.filter((item) => {
      return saleAttr.every((item1) => {
        return item.name != item1.saleName;
      });
    });
    return res;
  }
  console.log('fn',fn(allSaleAttr,saleAttr));

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转载自blog.csdn.net/Tianxiaoxixi/article/details/132360288