js数字金额转大写，javaScript数字金额转大写。

function numberParseChina(money) {
    
    
  //汉字的数字
  let cnNums = new Array(
    '零',
    '壹',
    '贰',
    '叁',
    '肆',
    '伍',
    '陆',
    '柒',
    '捌',
    '玖'
  )
  //基本单位
  let cnIntRadice = new Array('', '拾', '佰', '仟')
  //对应整数部分扩展单位
  let cnIntUnits = new Array('', '万', '亿', '兆')
  //对应小数部分单位
  let cnDecUnits = new Array('角', '分', '毫', '厘')
  //整数金额时后面跟的字符
  let cnInteger = '整'
  //整型完以后的单位
  let cnIntLast = '圆'
  //最大处理的数字
  let maxNum = 999999999999999.9999
  //金额整数部分
  let integerNum
  //金额小数部分
  let decimalNum
  //输出的中文金额字符串
  let chineseStr = ''
  //分离金额后用的数组，预定义
  let parts
  if (money == '') {
    
    
    return ''
  }
  money = parseFloat(money)
  if (money >= maxNum) {
    
    
    //超出最大处理数字
    return ''
  }
  if (money == 0) {
    
    
    chineseStr = cnNums[0] + cnIntLast + cnInteger
    return chineseStr
  }
  //转换为字符串
  money = money.toString()
  if (money.indexOf('.') == -1) {
    
    
    integerNum = money
    decimalNum = ''
  } else {
    
    
    parts = money.split('.')
    integerNum = parts[0]
    decimalNum = parts[1].substr(0, 4)
  }
  //获取整型部分转换
  if (parseInt(integerNum, 10) > 0) {
    
    
    let zeroCount = 0
    let IntLen = integerNum.length
    for (let i = 0; i < IntLen; i++) {
    
    
      let n = integerNum.substr(i, 1)
      let p = IntLen - i - 1
      let q = p / 4
      let m = p % 4
      if (n == '0') {
    
    
        zeroCount++
      } else {
    
    
        if (zeroCount > 0) {
    
    
          chineseStr += cnNums[0]
        }
        //归零
        zeroCount = 0
        chineseStr += cnNums[parseInt(n)] + cnIntRadice[m]
      }
      if (m == 0 && zeroCount < 4) {
    
    
        chineseStr += cnIntUnits[q]
      }
    }
    chineseStr += cnIntLast
  }
  //小数部分
  if (decimalNum != '') {
    
    
    let decLen = decimalNum.length
    for (let i = 0; i < decLen; i++) {
    
    
      let n = decimalNum.substr(i, 1)
      if (n != '0') {
    
    
        chineseStr += cnNums[Number(n)] + cnDecUnits[i]
      }
    }
  }
  if (chineseStr == '') {
    
    
    chineseStr += cnNums[0] + cnIntLast + cnInteger
  } else if (decimalNum == '') {
    
    
    chineseStr += cnInteger
  }
  return chineseStr
}