#include<stdio.h>
int main()
{
int n = 1, sum = 0;
for (n = 1; n <= 100; n++)
{
if (n % 10 == 6 || n / 10 == 6)
{
sum += n;
printf("%d\n", n);
}
}
printf("%d", sum);
return 0;
}
6、计算1~100以内所有含6的数的和。
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转载自blog.csdn.net/winds_tide/article/details/108028692#comments_25434190
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