面试-杨辉三角python递归实现，二进制转换

杨辉三角

def yang_hui(x,y):
    x=int(x)
    y=int(y)

    assert x>=y,'列数不应该大于行数'

    # x 表示行，y表示列
    if y==1 or y==x:
        return 1
    else:
        return yang_hui(x-1,y-1)+yang_hui(x-1,y)

x=input('输入第几行')
y=input('输入第几列')
result=yang_hui(int(x),int(y))
print(result)

#include <iostream>

using namespace std;

int yang_hui(int x, int y) 
{
	if (y==1)
	{	
		return 1;
	}
	else 
	{	
		if (y == x) {
			return 1;
		}
		else
			return yang_hui(x - 1, y - 1) + yang_hui(x - 1, y);

	}
	
}

void main() 
{
	int x=1, y=1;
	int result;
	cin >> x >> y;
	result = yang_hui(x, y);
	cout << "result" << result;
}

二进制

def tenTotwo(number):
    s = []
    binstring = ''
    while number > 0:
        rem = number % 2
        s.append(rem)
        number = number // 2
    while len(s) > 0:
        binstring = binstring + str(s.pop())
    return binstring

number=int(input('输入一个整数'))
bin_num1=bin(number)
print('转换后的二进制',bin_num1)
bin_num2=tenTotwo(number)
print('转换后的二进制',bin_num2)