【链表】翻转链表

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。

示例 1:
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输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]
示例 2:
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输入:head = [1,2]
输出:[2,1]
示例 3:

输入:head = []
输出:[]

提示:

链表中节点的数目范围是 [0, 5000]
-5000 <= Node.val <= 5000

题解:

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public ListNode reverseList(ListNode head) {
        if (head == null) {
            return head;
        }
        ListNode pre = null;
        ListNode curr = head;
        while (curr != null) {
            ListNode temp = curr.next;
            curr.next = pre;
            pre = curr;
            curr = temp;
        }
        return pre;
    }
}

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转载自blog.csdn.net/wjavadog/article/details/126735637
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