Android中判断当前网络是否可用

实现步骤:

1、获取ConnectivityManager对象

Context context = activity.getApplicationContext();
//获取手机所有链接管理对象(包括对Wi-Fi,net等连接的管理)
ConnectivityManager manager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);

2、获取NetworkInfo对象

//获取NetworkInfo对象
NetworkInfo[] info = manager.getAllNetworkInfo();

3、判断当前网络状态是否为连接状态

if (info[i].getState() == NetworkInfo.State.CONNECTED) {
   return true;
}

4、在AndroidManifest.xml中添加访问当前网络状态权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"></uses-permission>

完整代码:

public class MyFragment extends Fragment {
    @Override
    public void onViewCreated(@NonNull View view, @Nullable Bundle savedInstanceState) {
        super.onViewCreated(view, savedInstanceState);
        if (checkNetworkAvailable(getActivity())) {
            //有网络
            Toast.makeText(getContext(), "有网络!", Toast.LENGTH_SHORT).show();
        } else {
            //有网络
            Toast.makeText(getContext(), "无网络!", Toast.LENGTH_SHORT).show();
        }
    }


    //判断网络连接是否可用(返回true表示网络可用,false为不可用)
    public boolean checkNetworkAvailable(Activity activity) {
        Context context = activity.getApplicationContext();
        //获取手机所有链接管理对象(包括对Wi-Fi,net等连接的管理)
        ConnectivityManager manager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
        if (manager == null) {
            return false;
        } else {
            //获取NetworkInfo对象
            NetworkInfo[] info = manager.getAllNetworkInfo();
            if (info != null && info.length > 0) {
                for (int i = 0; i < info.length; i++) {
                    System.out.println(i + "状态" + info[i].getState());
                    System.out.println(i + "类型" + info[i].getTypeName());

                    // 判断当前网络状态是否为连接状态
                    if (info[i].getState() == NetworkInfo.State.CONNECTED) {
                        return true;
                    }
                }
            }
        }
        return false;
    }
}

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转载自blog.csdn.net/L73748196_/article/details/127982692