new Map()和for in两种方法判断一数据中对象和另一数组中对象是否想等

<!DOCTYPE html>
<html>
	<head>
		<meta charset="utf-8">
		<title></title>
	</head>
	<body>
		<script>
			var s1 = [{
					id: 1,
					name: '王贵'

				},
				{
					id: 2,
					name: '安娜'

				}
			]

			var s2 = [{
				id: 2,
				name: '安娜1'

			}]
			const merge = (s1, s2) => {
				const map = new Map()
				for (let i = 0; i < s1.length; ++i) {
					map.set(s1[i].id, s1[i].id).set(s1[i].name, s1[i].name)
					console.log(s1);
					console.log(map);
				}
				for (let i = 0; i < s2.length; ++i) {
					console.log(map.has(s2[i].id));
					console.log(map.has(s2[i].name));
				}
				return Array.from(map.values())
			}
			merge(s1, s2)
		</script>
	</body>
</html>
<!DOCTYPE html>
<html>

<head>
	<meta charset="utf-8" />
	<title></title>
</head>

<body>
	<script>
		var List = [{
			name: '王贵',
			phone: '18225517585',
			email: '[email protected]',
			province: '安徽省',
			city: '合肥市',
			district: '瑶海区',
			address: '华润熙云府34302',
			default: 0
		},
		{
			name: '安娜',
			phone: '18985623589',
			email: '[email protected]',
			province: '安徽省',
			city: '合肥市',
			district: '瑶海区',
			address: '华润熙云府3302',
			default: 0
		}
		]
		var perload = {
			name: '安娜',
			phone: '18985623589',
			email: '[email protected]',
			province: '安徽省',
			city: '合肥市1',
			district: '瑶海区',
			address: '华润熙云府3302',
			default: 0
		}
		function aaa() {
			let flag = false
			List.forEach(v => {
				for (var key in v) {
					console.log(perload[key]);
					if (v[key] != perload[key]) {
						flag = true
						return;
					} else {
						flag = false
					}
				}
			})
			if(flag) {
				alert('添加')
			}
		}
		aaa()
	</script>
</body>

</html>

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转载自blog.csdn.net/qq_34093387/article/details/127011214
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