shell脚本计算输入日期是该年的第几天

07.sh

#!/bin/bash
read -p "请输入年月日" year mouth day
a=0
if [ $(($year%400)) -eq 0 -o $(($year%4)) -eq 0 -a $(($year%100)) -ne 0 ]
then 
	let a+=1	
fi
if [ $mouth -gt 0 -a $mouth -le 12 ]
then
	flag=0
	case $mouth in
		[13578]|10|12)
			if [ $day -gt 0 -a $day -le 31 ]
			then
				((flag=0))
			else
				((flag=1))
			fi
			;;
		2)
			if [ $day -gt 0 -a $day -le $((28+$a)) ]
			then
				((flag=0))
			else
				((flag=1))
			fi
			;;
		*)
			if [ $day -gt 0 -a $day -le 30 ]
			then
				((flag=0))
			else
				((flag=1))
			fi
			;;

		esac
		if [ $flag -eq 0 ]
		then
			today=0;
			case $mouth in
				1)
					let today=${
    
    day};;
				2)
					today=$((31+$day));;
				3)
					today=$((31+28+$a+$day));;
				4)
					today=$((30*3+$a+$day));;
				5)
					today=$((30*4+$a+$day));;
				6)
					today=$((30*5+1+$a+$day));;
				7)
					today=$((30*6+1+$a+$day));;
				8)
					today=$((30*7+2+$a+$day));;
				9)
					today=$((30*8+3+$a+$day));;
				10)
					today=$((30*9+3+$a+$day));;
				11)
					today=$((30*10+4+$a+$day));;
				12)
					today=$((30*11+4+$a+$day));;
			esac	
			echo "这是今年的第$today天"
		else
			echo "天数输入错误"
		fi

	else
		echo "月份输入错误"
fi

08.sh
输入数字求和

#!/bin/bash
read -p "请输入数字" a b
for i in $(seq $a $b)
#for i in {1..100}
#for((i=0;i<=100;i++))
#for i
do 
	((sum+=$i))
done
echo $sum

九九乘法表
09.sh

#!/bin/bash
for i in {
    
    1..9}
do
	for j in `seq $i 9`
	do
		echo -n "$i x $j = $(($i*$j))   "
	done
	echo
done