实现C++中atoi函数,字符串转整型
#include <iostream>
using namespace std;
int atoi_my(char* str){
static const int MAX_INT = (int)((unsigned)~0 >> 1);
int s;
bool flag=true;
while(*str==' '){
++str;
}
if(*str=='-'||*str=='+'){
if(*str=='-'){
flag=false;
}
++str;
}
while(*str>='0'&&*str<='9'){
if(s>MAX_INT/10){
s=MAX_INT;
break;
}
s=s*10+(*str-'0');
++str;
}
return s*(flag?1:-1);
}
int main() {
char* c=new char[100];
while(1){
cin>>c;
int ci=atoi_my(c);
cout<<ci<<endl;
}
return 0;
}