输入某一年的第几天,计算并输出它是这一年的第几月第几日

#include <stdio.h>
void fun(int year, int x, int *month, int *day);
int main()
{
    
    
	int year, x, month, day;
	
	scanf("%d %d", &year, &x);
	fun(year, x, &month, &day);
	return 0;
}
void fun(int year, int x, int *month, int *day)
{
    
    
	int i = 0, t, flag;
	int a[2][12] = {
    
    {
    
    31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
					{
    
    31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}};
	if((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
		flag = 1;
	else 
		flag = 0;
	t = x;
	if((flag == 1 && x > 366) || (flag == 0 && x > 365))
	{
    
    
		printf("输入不合法\n");
	}
	else
	{
    
    
		while(t > a[flag][i])
		{
    
    
			t = t - a[flag][i];
			i++;
		}
		*month = i + 1;
		*day = t;
		printf("是%d月%d日\n", *month, *day);
	}
	
}

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转载自blog.csdn.net/jiuchena/article/details/103434739