JavaSE——按顺序输出一个数字的每一位(递归实现)

代码演示

import java.util.Scanner;


public class Test {
    
    
 public static void print(int n) {
    
    
        if(n < 10) {
    
    
            System.out.print(" "+n+" ");
        }else {
    
    
            print(n/10);
            System.out.print(" "+n%10+" ");
        }
    }

    public static void main(String[] args) {
    
    
        Scanner sc  = new Scanner(System.in);
        int n = sc.nextInt();
        print(n);
    }
    
}