题目:有3个线程,ID号分别为ABC,启动这3个线程,使其输出它的ID号3次,ABCABCABC。
思路一 要按照顺序输出ABC,循环3次,就要控制三个线程的同步,也就是说要让三个线程轮流输出,直到3个ABC全部输出则结束线程。这里可以使用Lock对象来控制三个线程的同步,用一个int型变量state标识由哪个线程输出。
public class ThreadTest { private static int state = 0; private static final Lock lock = new ReentrantLock(); public static void main(String[] args) throws Exception { Thread A = new Thread(new Runnable() { @Override public void run() { while (state <= 8) { lock.lock(); //再进行一次 state <= 8的判断 if (state % 3 == 0 && state <= 8) { System.out.println(Thread.currentThread().getName() + ":" + state); state++; } lock.unlock(); } } }, "A"); Thread B = new Thread(new Runnable() { @Override public void run() { while (state <= 8) { lock.lock(); if (state % 3 == 1 && state <= 8) { System.out.println(Thread.currentThread().getName() + ":" + state); state++; } lock.unlock(); } } }, "B"); Thread C = new Thread(new Runnable() { @Override public void run() { while (state <= 8) { lock.lock(); if (state % 3 == 2 && state <= 8) { System.out.println(Thread.currentThread().getName() + ":" + state); state++; } lock.unlock(); } } }, "C"); A.start(); B.start(); C.start(); } }
思路二 上述思路中引入了一个state来控制轮到谁来执行,同时也要保证在输出打印线程名之前再次判断state <= 8,防止打印次数超出。我们也可以给每个线程指定信号量Semaphore来控制输出的顺序,实现代码如下:
public class ThreadTest { private static Semaphore semaphoreA = new Semaphore(1); private static Semaphore semaphoreB = new Semaphore(1); private static Semaphore semaphoreC = new Semaphore(1); public static void main(String[] args) throws Exception { Thread A = new Thread(new Runnable() { @Override public void run() { for (int state = 0; state < 3; state++) { try { semaphoreA.acquire(); System.out.println(Thread.currentThread().getName() + ":" + state); semaphoreB.release(); } catch (InterruptedException e) { e.printStackTrace(); } } } }, "A"); Thread B = new Thread(new Runnable() { @Override public void run() { for (int state = 0; state < 3; state++) { try { semaphoreB.acquire(); System.out.println(Thread.currentThread().getName() + ":" + state); semaphoreC.release(); } catch (InterruptedException e) { e.printStackTrace(); } } } }, "B"); Thread C = new Thread(new Runnable() { @Override public void run() { for (int state = 0; state < 3; state++) { try { semaphoreC.acquire(); System.out.println(Thread.currentThread().getName() + ":" + state); semaphoreA.release(); } catch (InterruptedException e) { e.printStackTrace(); } } } }, "C"); semaphoreB.acquire(); semaphoreC.acquire(); A.start(); B.start(); C.start(); } }