1. 查询所有列
题目:现在运营想要查看用户信息表中所有的数据,请你取出相应结果
建表语句:
drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`province` varchar(32) NOT NULL);
INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学','Shanghai');
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学','ZheJiang');
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学','Shandong');
解题答案:
-- 写法一
SELECT * from user_profile;
-- 写法2
SELECT id,device_id,gender,age,university,province from user_profile;
2. 查询多列
题目:现在运营同学想要用户的设备id对应的性别、年龄和学校的数据,请你取出相应数据
建表语句:
drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`province` varchar(32) NOT NULL);
INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学','Shanghai');
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学','ZheJiang');
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学','Shandong');
解题答案:
SELECT device_id,gender,age,university from user_profile
3. 查询结果去重
题目:现在运营需要查看用户来自于哪些学校,请从用户信息表中取出学校的去重数据。
建表语句:
drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`province` varchar(32) NOT NULL);
INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学','Shanghai');
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学','ZheJiang');
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学','Shandong');
解题答案:
-- 1. 使用DISTINCT:
SELECT DISTINCT university from user_profile;
-- 2. 使用group by:
SELECT university from user_profile GROUP BY university;
4. 查询结果限制返回行数
题目:现在运营只需要查看前2个用户明细设备ID数据,请你从用户信息表 user_profile 中取出相应结果。
建表语句:
drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`province` varchar(32) NOT NULL);
INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学','Shanghai');
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学','ZheJiang');
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学','Shandong');
解题答案:
select device_id FROM user_profile WHERE id in(1,2)
select device_id FROM user_profile WHERE id <= 2
select device_id FROM user_profile limit 2
select device_id FROM user_profile limit 0,2
5. 将查询后的列重新命名
题目:现在你需要查看前2个用户明细设备ID数据,并将列名改为 ‘user_infos_example’,,请你从用户信息表取出相应结果。
建表语句:
drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`province` varchar(32) NOT NULL);
INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学','Shanghai');
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学','BeiJing');
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学','ZheJiang');
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学','Shandong');
解题答案:
select device_id as user_infos_example from user_profile limit 0, 2;
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