一个sql的应用(加入行,并分解字段)
select t.id,substr(t.uids,instr(t.uids,',',rownum,rownum)+1,3) from TEST11 t connect by rownum<=3;
//用正则
select t.id,
dbms_lob.substr(regexp_substr(t.uids, '[^,]+', 1, x.n)) as uids
from TTTTTT t,
(select rownum n
from dual
connect by rownum <
(select length(f.uids) - length(replace(f.uids, ',', '')) + 2 n
from TTTTTT f)) x
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转载自love398146779.iteye.com/blog/1569114
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