1.5 编程基础之循环控制 10 满足条件的数累加

#include <stdio.h>
#include <stdlib.h>
int main()
{
	int m,n,i,sum=0;
	
	scanf("%d%d",&m,&n);
	
	for(i=m;i<=n;i++)
	{
		if(i%17==0)
		{
			sum+=i;
		}
	}
	
	printf("%d",sum);
	
	return 0;
}

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 python代码

"""
1.5编程基础之循环控制 10 满足条件的数累加
http://noi.openjudge.cn/ch0105/10/

https://blog.csdn.net/weixin_45852964/article/details/103199313
https://blog.csdn.net/weixin_45852964/article/details/103375233
https://blog.csdn.net/weixin_45852964/article/details/103586946
https://blog.csdn.net/weixin_45852964/article/details/103481658

"""
m,n=map(int,input().split())
sum =0
for i in range(m,n+1):
    if i%17==0:
        sum+=i
print(sum)