1.返回下一个星期一对应的日期
Select NEXT_DAY(sysdate,'星期一') From dual;
2.返回星期几
select to_char(sysdate,'DAY') as weekday from dual;
3.根据星期几排序
从星期天开始(1代表星期天)
select time,to_char(begintime,'d') from t order by to_char(time,'d');
从星期一开始
select begintime,trim(to_char(t.begintime, 'DAY')) dd,decode(trim(to_char(t.time, 'DAY')),
'MONDAY',
1,
'TUESDAY',
'2',
'WEDNESDAY',
'3',
'THURSDAY',
'4',
'FRIDAY',
'5',
'SATURDAY',
'6',
'SUNDAY',
'7') from t
order by 3 ;
oracle日期函数备忘
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转载自myjcwy.iteye.com/blog/1635080
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