# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def hasCycle(self, head: ListNode) -> bool:
#判断是否存在环,是leetcode142的前提条件
slow, fast = head, head
while(fast and fast.next):
slow, fast = slow.next, fast.next.next
if(slow == fast):
return True
else:
return False
环形链表python3(leetcode141)
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转载自blog.csdn.net/ziqingnian/article/details/121923360
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