数据库面试题-胜负统计
mysql 第一种解决方法
SELECT datetime 日期, SUM(if(result='胜',1,0)) 胜, SUM(if(result='负',1,0)) 负 from t_nba group by datetime
通用sql,使用left join完成
SELECT t.*,t2.fu from (SELECT DISTINCT(t_nba.datetime) datetime, t1.sheng from t_nba LEFT JOIN ( SELECT datetime , COUNT(*) as sheng from t_nba where result='胜' GROUP BY datetime ) as t1 on t_nba.datetime = t1.datetime ) t LEFT JOIN ( SELECT datetime , COUNT(*) as fu from t_nba where result='负' GROUP BY datetime ) as t2 ON t.datetime = t2.datetime