assume cs:code
code segment
start:
mov ax,2000h
mov ds,ax
mov bx,0
s:
mov cl,[bx]
mov ch,0
inc cx ;此条指令为题目要求补全的指令
inc bx
loop s
ok:
dec bx
mov dx,bx
mov ax,4c00h
int 21h
code ends
end start
【汇编语言】王爽第三版----------------检测点9.3
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