map转成url拼接请求参数

两种方法都可灵活运用

方法一

public String buildMap(Map<String, String> map) {
        StringBuffer sb = new StringBuffer();
        if (map.size() > 0) {
            for (String key : map.keySet()) {
                sb.append(key + "=");
                if (StringUtils.isEmpty(map.get(key))) {
                    sb.append("&");
                } else {
                    String value = map.get(key);
                    try {
                        value = URLEncoder.encode(value, "UTF-8");
                    } catch (UnsupportedEncodingException e) {
                        e.printStackTrace();
                    }
                    sb.append(value + "&");
                }
            }
        }
        return sb.toString();
    }

方法二

	/**
	 * @param paramsMap
	 * @return
	 */
	private static String getParams(Map<String, String> paramsMap) {
		String params = "";
		Iterator<String> iterator = paramsMap.keySet().iterator();
		while(iterator.hasNext()) {
			String key = iterator.next();
			params += key + "=" + paramsMap.get(key) + "&";
		}
		params = params.substring(0, params.length() - 1);
		return params;
	}

参考：https://blog.csdn.net/zls_1029/article/details/77643553